A bar of magnetic moment `2.5 Am^(2)` is free to rotate about a vertical axis through its centre . The magnet is released from the rest from the east - west direction . Find the kinetic energy of the magnet as it aligns itself in the north - south direction . The horizontal component of earth's magnetic field is `0.3 G`

A bar magnet of magnetic moment 2.0 A m^2 is free to rotate about a vertical axis through its centre. The magnet is released from rest from the east-west position. Find the kinetic energy of the magnet as it takes the north-south position. The horizontal component of the earth's magnetic field is B = 25 muT .

A bar magnet of magnetic moment 2.0 A-m^2 is free to rotate about a vertical axis through its centre. The magnet is released from rest from the east west position. Find the kinetic energy of the magnet as it takes the north south position. The horizontal component of the earth's magnetic field as B=25muT . Earth's magnetic field is from south to north.

A bar magnet of moment 40 A-m^(2) is free to rotate about a vetical axis passing through its centre. The magnet is released from rest from east west direction. The kinetic energy of the magnet as it takes north-south direction is (B_(H)=30muT)

A bar magnet of magnetic moment 2Am^(2) is free to rotate about a vertical axis passing through its centre. The magnet is released from rest from east-west position. Then the KE of the magnet as it takes N-S position is (B_(H)=25muT)

A bar magnet of magnetic moment 4Am^(2) is free to rotate about a vertical axis passing through it centre.The magnet is released from rest from east-west position.Then K.E of the magnet as it takes north-south position is B_(H)=20 mu T

49.A bar magnet of magnetic moment 2Am^(2) is free to rotate about a vertical axis passing through its centre.The magnet is released from rest east-west position.Then the K.E of the magnet as it takes north-south position is (2n+40)mu J then "n" is ( B_(H)=25 mu T )

A 30 cm long bar magnet is placed in the magnetic meridian with its north pole pointing south. The neutral point is obtained at a distance of 40 cm from the centre of the magnet. Pole strength of the magnet is (The horizontal component of earth’s magnetic field is 0.34 Gauss)

A magnetic dipole of magnetic moment 0.72(sqrt(2) Am^2) is placed horizontally with the north pole pointing towards east. Find the position of the neutral point if the horizontal component of the earth's magnetic field is 18 muT .

Assertion: A compass needle when placed on the magnetic north pole of the earth rotates in vertical direction. Reason: The earth has only horizontal component of its magnetic field at the north poles.