If a planet consits of a satellite whose mass and radius were both half that of the earth, the acceleration due to gravity at its surface would be (g on earth=`9.8m//sec^(2)`)

If a planet consists of a satellite whose mass and radius were both half that of the earh, then acceleration due to gravity at its surface would be

Suppose a planet exists whose mass and radius both, are half those of earth. Calculate the acceleration due to gravity on the surface of this planet.

The mass of a planet is (1//10)^("th") that of earth and its diameter is half that of earth the acceleration due to gravity is

Suppose a planet exist whose mass and diameter both are twice of earth. Calculate acceleration due to gravity on this planet. On earth, take g=9.8 m//s .

Find the binding energy of a satellite of mass m in orbit of radius r , (R = radius of earth, g = acceleration due to gravity)

Mass remaining constant, the radius of the earth shrinks by 1%. The acceleration due to gravity on the earth's surface would

The value of acceleration due to gravity 'g' on the surface of a planet with radius double that of the earth and same mean density as that of the earth is ( g_(e) =acceleration due to gravity on the surface of the earth )

If the radius of the earth were to shrink by 1% its mass remaining the same, the acceleration due to gravity on the earth's surface would

The mass of a planet and its diameter are three times those of earth's. Then the acceleration due to gravity on the surface of the planet is : (g =9.8 ms^(-2))