Graph between log k and (1)/(T) (k is ra...

Graph between log k and `(1)/(T)` (k is rate constant in `s^(-1)` and T is the temperature in K) is a straight line. As shown in figure if OX = 5 and slope of the line `=- (1)/(2.303)`then `E_(a)` is :

Similar Questions

Explore conceptually related problems

Graph between log k and 1//T [ k rate constant (s^(-1)) and T and the temperature (K) ] is a straight line with OX =5, theta = tan^(-1) (1//2.303) . Hence -E_(a) will be

The graph between log k versus 1//T is a straight line.

A graph plotted between log k vs (1)/(T) is represented by

The graph between the log K versus 1/T is a straight line. The slope of the line is

If a graph is plotted between ln k and 1//T for the first order reaction, the slope of the straight line so obtained is given by

For a first order reaction, the plot of log k against 1/T is a straight line. The slope of the line is equal to

Graph between log k and `(1)/(T)` (k is rate constant in `s^(-1)` and T is the temperature in K) is a straight line. As shown in figure if OX = 5 and slope of the line `=- (1)/(2.303)`then `E_(a)` is :

Similar Questions

Recommended Questions