In what time after its motion begins, will a particle oscillating according to the equation, `y=7 sin 0.5 pi ` t move from the mean position to maximum displacement ?

How much time will a particle oscillating according to equation y = 10 sin (0.9 pit )m take to move from mean position to position of maximum displacement ?

A particle is oscillating according to the equation X=7 cos 0.5 pit , where t is in second. The point moves from the position of equilibrium to maximum displacement in time

A particle moves on y-axis according to the equation y = A +B sin omegat . Amplitude of motion is

A particle is osicllating according to the equation X= 7 cos (0.5 pi t) , where t is in second. The point moves from the position of equilibrium to maximum displacement in time

A particle is oscillating according to the equation x = 8 cos pi t , where 't' is in second. The particle moves from the position of equilibrium to maximum displacement in time

A particle is oscillating according to the equation x = 10cos2pit , where 't' is in seconds. The particle moves from the position of maximum displacement to equilibrium in time.

A particle oscillates, according to the equation x = 5 cos (pit//2) m. Then the particle moves from equilibrium position to the position of maximum displacement in time of

A particle is executing SHM of periodic time T the time taken by a particle in moving from mean position to half the maximum displacement is (sin 30^(@)=0.5)