Power of a man who can chew `0.3 kg` ice in one minute is (in cal/s).

Find the power of a person who can chew 30g of ice in one minute. Latent heat of ice =80cal//gm , J=4.2 joule // cal.

Calculate the horse power of a man who can chew ice at the rate of 60g min.^(-1) . Given J = 4.2 J cal^(-1) and altent heat of ice = 80 cal g^(-1), 1hp = 746W .

One end of metal bar of area of cross section 5cm^(2) and 25cm in length is in steam other in contact with ice, the amount of ice melts in one minute is (L_(ice) =80 cal//gm,K=0.8cgs" uits") .

The power of a system which can convert 10 kg of water at 30^@ C into ice 0^@ C in one minute (L_(ice) = 336000 J//Kg and S_(water) = 4200 J//kg//K ) will be

What is the power of an engine which can lift 600 kg of water per minute from 20 m deep well?

Heat required to melt 1 g of ice is 80 cal. A man metls 60 g of ice by chewing in one minute. His power is

What is the horse power applied by a person while chewing 100g of ice per minute ? Given J = 4.2 joule per calorie.

Latent heat of ice 80 cal/gm . A man melts 60 g of ice by chewing in 1 minute . His power is

Latent heat of ice is 80 calgm. A man meits 60 gm of ice by chewing in 1 minute. His power is