Home
Class 12
CHEMISTRY
2.68xx10^(-3) moles of solution containi...

`2.68xx10^(-3)` moles of solution containing anion `A^(n+)` require `1.61xx10^(-3)` moles of `MnO_(4)^(-)` for oxidation of `A^(n+)` to `AO_(3)^(-)` in acidic medium. What is the value of `n`?

Promotional Banner

Similar Questions

Explore conceptually related problems

3.90xx10^(-3) moles of a solution containing an ion A^(n+) require 2.34xx10^(-3) moles of MnO_4^(-) for the oxidation of A^(n+) " to " AO_3^(-) in acidic medium . What is the value of n ?

4 " mol of "a solution containing A^(n+) requried 1.6 mon of MnO_(4)^(ɵ) for the oxidation to A^(n+) to AO_(3)^(ɵ) in acidic medium. The value of n is

A solution contaning 2.7 xx 10^(-3) mol of A^(2+) "ion required" 1.6 xx 10^(-3)mol of MnO_(4)^(2-) for the oxidation of A^(2+) "to" AO_(3)^(-) the medium is:

6 " mol of "a solution A^(n+) requires 2 " mol of " Cr_2O_7^(2-) ions for the oxidation of A^(n+) to AO_3^(ɵ) in acidic medium the value of n is (a). 1 (b). 2. (c). 3. (d). 4.

10 moles of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium. The value of 'x' is :

1 mole of ferric oxalate is oxidised by x mole of MnO_(4)^(-) in acidic medium, Hence value of x is: