Let the base of a triangle lie along the line x = a and be of length 2a. The area of this triangles is `a^(2)`, if the vertex lies on the line

Let the base of a triangle lie along the line x=a and be of length a. The area of this triangle is a2, if the vertex lies on the line

The base of a triangle lies along x= 1and is of length 1. The area of triangle is 1. The locus of vertex is

The base of a triangle lies along x=5 and is of length 1 .The area of triangle is 1 . The locus of vertex is

The base of an equilateral triangle is along theline given by 3x+4y=9 .If a verter of the triangle is (1,2), then the length of a side of the triangle is

The vertices of the base of an isosceles triangle lie on a parabola y^2 = 4x and the base is a part of the line y = 2x - 4 . If the third vertex of the triangle lies on the x-axis, its coordinates are

Let A(-3,2) and B(-2,1) be the vertices of a triangle ABC. If the centroid of this triangle 1 ies on the line 3x+4y+2=0 then the vertex C lies on the line :

An isosceles triangle is inscribed in the parabola y^2 = 4ax with its base as the line joining the vertex and positive end of the latus rectum of the parabola. If (at^2, 2at) is the vertex of the triangle then

The area of triangle formed by the lines l_1 and l_2 and the x-axis is: