The lines `p(p^2+1)x-y+q=0` and `(p^2+1)^2x+(p^2+1)y+2q=0` are perpendicular to a common line for

The lines p(p^(2)+1)x-y+q=0 and (p^(2)+1)^(2)x+(p^(2)+1)y+2q=0 are perpendicular to a common line for

The lines quad p(p^(2)+1)x-y+q=0 and (p^(2)+1)^(2)x+(p^(2)+1)y+2q=0 are perpendicular to a common line for (1) no value of p(4) more than two values of p two values of p(4) more than two values of p

If the lines (p-q)x^2+2(p+q)xy+(q-p)y^2=0 are mutually perpendicular , then

P is a point on the parabola y^(2)=4x and Q is Is a point on the line 2x+y+4=0. If the line x-y+1=0 is the perpendicular bisector of PQ, then the co-ordinates of P can be:

The pair of equations (p^(2) -1)x + (q^(2) -1) y + r=0 and (p+1) x + (q-1) y + r=0 have infinitely many solutions, then which of the following is true ?

Let P_(1):x-2y+3z=5 and P_(2):2x-3y+z+4=0 be two planes. The equation of the plane perpendicular to the line of intersection to the line of intersection of P_(1)=0 and P_(2)= and passing through (1,1,1) is