A freely falling body takes T second to travel first (1/x)th distance.Then,time of descent is

A freely falling body takes 't' second to travel first 1/xth distance.Then,time of descent is

" A freely falling body takes "' second to travel first "(1/x)^(th)" distance.Then,time of descent is "

A freely falling body takes t second to travel (1//x)^(th) distance then time of descent is

A freely falling body travels-- of total distance in 5th second

If a freely falling body travels in the last second, a distance equal to the distance travelled by it in the first three second, the time of the travel is

Distance travelled by a freely falling body in the nth second is equal to 'n' sec find the value of n

The distances covered by a freely falling body in its first, second, third, ……, b^(th) seconds of its motion

IF a freely falling body covers halfs of its total distance in the last second of its journey. Find its time of fall

A freely falling body takes 4s to reach the ground. One second after release, the percentage of its potential energy, that is still retained is

A freely falling body travelled x m in n^("th") second. Then distance travelled in n-1^("th") second is