A body is projected horizontally from a height of 78.4m with a velocity 10m/s .Its velocity after 3 seconds is ?[g=10m/`s^(2)`]

A body is projected horizontally from a height of 78.4 m with a velocity 10 ms^(-1) .Its velocity after 3 seconds is (g=10 m//s^(2)) (Take direction of projection as i and vertically upward direction as j )

A body is projected horizontally from the top of a tower of height 10m with a velocity 10m/s .Its velocity after 1 second is

A body is projected horizontally with a velocity of 4sqrt2 m/sec . The velocity of the body after 0.7 seconds (Take g = 10 m/s^2 ) will be nearly

A body is projected horizontally from the top of a tower of height 4.9m with a velocity of 9.8m/s. The velocity with which the body strikes the ground is?

A body is projected horizontally from the top of a tower with a velocity of 20m/s .After what time the vertical component of velocity is four times the horizontal component of velocity (g=10m/s^(2))

A particle of mass 50 g is projected horizontally from the top of a tower of height 50 m with a velocity 20m//s . If g=10m//s^(2) , then find the :-

A body is projected horizontally with a velocity of 4sqrt2m//sec . The velocity of the body after 0.7 seconds will be bearly (Take g = 10 m/sec^(2) )

A body is projected with velocity 60m//s at 30^(@) to the horizontal.The velocity of the body after 3 seconds is

A ball is projected from a 500m high towe with velocity of 100m/s horizontally. It lands on a 375cm high tower. Take g=10m//s^(2)) Match the following two Tables.