Given that `A(1,-1)` and locus of B is `x^2 + y^2 = 16`.1f `P` divides `AB` in the ratio `3: 2` then locus of `P` is

Given that A(1,-1) and locus of B is x^(2)+y^(2)=16.1fP divides AB in the ratio 3:2 then locus of P is

A=(2,-1) locus of B is x^(2)+y^(2)=25. If P divides AB in the ratio 1:2 then locus of P is

A variable line through the point (6/5, 6/5) cuts the coordinates axes in the point A and B . If the point P divides AB internally in the ratio 2:1 , show that the equation to the locus of P is : 5xy = 2( 2x+y) .

Let A(1,-1,2) and B(2,3-1) be two points. If a point P divides AB internally in the ratio 2:3 , then the position vector of P is

Let P be a point on x^2 = 4y . The segment joining A (0,-1) and P is divided by point Q in the ratio 1:2, then locus of point Q is

A (2, 3) is a fixed point and Q(3 cos theta, 2 sin theta) a variable point. If P divides AQ internally in the ratio 3:1, find the locus of P.

P(-1,4),Q(11,-8) divides AB harmonically in the ratio 3:2 then A,B are

A variable line through the point ((6)/(5),(6)/(5)) cuts the coordinate axes at the points A and B respectively. If the point P divides AB internally in the ratio 2:1 , then the equation of the locus of P is

Let PQ be a double ordinate of the parabola,y^(2)=-4x where P lies in the second quadrant.If R divides PQ in the ratio 2:1 then teh locus of R is