Find `int[log(logx)+1/((logx)^2)]dx`

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"F i n d"int[log(logx)+1/((logx)^2)]dx Find log (log x)+ |dx 2 (log x)

int[(1)/(logx)-(1)/((logx)^(2))]dx=

Evaluate : int {log(logx)+(1)/((logx)^(2))}dx

Evaluate the following integrals: int{log(logx)+(1)/((logx)^(2))}dx

int(log(logx))/(x.logx)dx=

int(log(x//e))/((logx)^(2))dx=

Evaluate : int[(1)/(logx)-(1)/((log x)^(2))]dx