If the vertex = (2,0) and the extremities of the latus rectum are (3, 2) and (3, -2), then the equation of the parabola is:

The vertex of a parabola is (2,2) and the coordinats of its two extrremities of latus rectum are (-2,0) and (6,0). Then find the equation of the parabola.

Find the equation of the parabola the extremities of whose latus rectum are (1,2) and (1,-4).

Let A be the vertex and L the length of the latus rectum of the parabola,y^(2)-2y-4x-7=0 The equation of the parabola with A as vertex 2L the length of the latus rectum and the axis at right angles to that of the given curve is:

Find the extremities of latus rectum of the parabola y=x^(2)-2x+3

The extreme points of the latus rectum of a parabola are (7,5) and (7,3). Find the equation of the parabola and the points where it meets the coordinate axes.

Find the equation of the parabola whose vertex is (2,3) and the equation of latus rectum is x=4. Find the co-ordinates of the point of intersection of this parabola with its latus rectum.

Find the measure of the angle subtended by the latus rectum of the parabola y^(2) = 4ax at the vertex of the parabola .