If `a !=b != c`, lf `ax + by + c = 0, bx + cy + a = 0 and cx+ay + b = 0` are concurrent. Then the value of `2^(a^2 b^-1 c^-1) 2^(b^2 c^-1 a^-1) 2^(c^2 a^-1 b^-1)`

If the lines ax+by+c=0,bx+cy+a=0 and cx+ay+b=0 be concurrent,then:

If the lines ax+by+c=0,bx+cy+a=0 and cx+ay+b=0a!=b!=c are concurrent then the point of concurrency is

If the lines ax+12y+1=0 bx+13y+1=0 and cx+14y+1=0 are concurrent then a,b,c are in

If a+b+c!=0 ,ax+by+c=0, bx+cy+a=0, cx+ay+b=0 are concurrent then (a^(2)+b^(2)+c^(2))/(ab+bc+ca)=

If the lines (a-b-c) x + 2ay + 2a = 0 , 2bx + ( b- c - a) y + 2b = 0 and (2c+1) x + 2cy + c - a - b = 0 are concurrent , then the prove that either a+b+ c = 0 or (a+b+c)^(2) + 2a = 0