`62.5 xx 10^(18)` electrons per second are flowing through a wire of area of cross-section `0.1m^(2)`, the value of current flowing wil be

62.5 XX 10^(18) electorns per second are flowing through a wire of area of cross-section 0.1 m^(2) , the value of current flowing will be

If 10^(6) electrons/s are flowing through an area of cross section of 10^(-4) m^(2) then the current will be:-

A flow of 10^7 electrons per second in a conducting wire constitutes a current of

An electron beam has an aperture of 1.0 mm^(2) . A total of 6xx10^(16) electrons flow through any perpendicular cross-section per second. Calculate (i) the current (ii) the current density in the electron beam.

An electron beam has an aperture of 2mm^(2) . A total of 7xx10^(16) electrons flow through any perpendicular cross-section per second. Calculate the current density in the electron beam.

A metal wire of cross-sectional area 1m m^(2) contains 5xx10^(22) electrons per cm^(3) . If the electrons move along the wire with average drift velocity 1m m//s , then the current in the wire is ( e=1.6xx10^(-19)C )