अवकल समीकरण `(dy)/(dx) =(x+y +1)/(2x+2y+3)` का हल ज्ञात कीजिए।

(dy)/(dx)=(x-y+3)/(2x-2y+5)

(dy)/(dx)=(x+y+7)/(2x+2y+3)

x (dy)/(dx) - y = 2x ^(3)

dy/dx =(y)/(2y^3+x)

(dy)/(dx)+(1)/(2x)y=(x)/(y^(3))

(dy)/(dx)=(y^(3)-2x^(2)y)/(x^(3))

(dy) / (dx) = (1- (2x + 3y)) / (2x + 3y-5)

(dy)/(dx)-2/(x+1) y=(x+1)^3

If 9x^2+y^2=37 and xy = 2 , x, y> 0 , then the value of (27x^3+y^3) is : यदि 9x^2+y^2=37 और xy = 2 , x, y> 0 , तो (27x^3+y^3) का मान ज्ञात कीजिए ।

dy/dx - (2y)/(x+1) = (x+1)^3