The value of Henry's law constant for some gases at 293 K is given below. Arrange the gases in the increasing order of their solubility .
He:144.97 kbar, `H_2`:69.16 kbar, `N_2`:76.48 kbar, `O_2`: 34.86 kbar

The value of Henry's law constant for few gases at 298 K is given below. Arrange these gases in the increasing order of their solubility . N_2 : 76.48 kbar. O_2 : 34.86 kbar, H_2 : 69.16 kbar

Arrange the gases, H_(2) , N_(2), He, O_(2) in increasing rate of diffusion.

The values of the Henry's law constant of Ar, CO_2 , CH_4 ,and O_2 in water at 25^@C are 40.30,1.67,0.41 and 34.86 kbar, respectively, The order of their solubility in water at the same temperature and pressure is

For real gases the relation between p, V and T is given by c=van der Waal's equation (p+ (an^(2))/V^(2)) (V-nb)=nRT where, 'a' and 'b' are van der Waal's constanrs, 'nb' is approximately equal to the total volume of the molecules of a gas. 'a' is the measure of magnitude of intermolecular attraction. (i) Arrange the following gases in the increasin order of 'b'. give reason. O_(2), CO_(2), H_(2), He (ii) Arrange the following gases in the decreasing order of magnitude of 'a'. Give reason. CH_(4), O_(2), H_(2)

The correct increasing order of Vanderwaal constant 'b' for H_(2) , O_(2) , CO_(2) , He gases is

K_(H) value for Ar(g),CO_(2)(g),HCHO(g)and CH_(4)(g) are 40.39,1.67,1.83xx10^(-5)and0.413 respectively. Arrange these gases in the order of their increasing solubility.

K_(H) value for' Ar_(g),CO_(2g),HCHO_(g) and CH_(4g) are 40.39, 1.67, 1.83xx10^(-5) and 0.413 respectively. Arrange these gases in the order of their in creasing solubility.