An ideal battery of emf 2 V and a series resistance R are connected in the primary circuit of a potentiometer of length 1 m and resistance `5Omega` The value of R, to give a potential difference of 5 m V across 10 cm of potentiometer wire is

AN ideal battery of 4 V and resistance R are connected in series in the primary circuit of a potentiometer of length 1 m and the value of 5 ohm, to give a difference of 5mV across 10 cm of potentiometer wire , is :

In figure AB is a potentiometer wire of length 10 m and resistance 1Omega . The balancing length for 2V potential drop is 18 m. The e.m.f. of the battery E is

A battery of emf 26V and internal resistance 0.4 ohm is connected to a resistance of 10ohm and a potentiometer wire of length 10m. What is the potential gradient on the wire if the resistance of the potentiometer wire is 5 ohm –

A cell of e.m.f 1.5V and negligible internal resistance is connected in series with a potential meter of length 10 m and total resistance 20 Omega . What resistance should be introduced in the resistance box such that the potential drop across the potentiometer is one microvolt per cm of the wire?

A potentiometer consists of a wire of length 4 m and resistance 10Omega . It is connected to a cell of emf 2V.The potential gradient of the wire is

If a ideal battery of e.m.f.10 V is connected with external resistance 9Omega and a wire of length 10 m and resistance 1Omega in series as shown in potentiometer wire

A potentiometer consists of a wire of length 4 m and resistance 10 Omega . If is connected of cell of emf 2V . The potential difference per unit length of the wire will be

A resistance of 990Omega and a cell of emf 2 V is connected in series with a potentiometer wire having a length 2 m and resistance 10Omega . The potential gradient along the wire will be