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In an experiment according to set up, wh...

In an experiment according to set up, when `E_(1)=12` volt and internal resistance zero, E = 2 volt. The galvanometer reads zero, then X would be-

A

200

B

500

C

100

D

10

Text Solution

Verified by Experts

The correct Answer is:
C
Voltage across X is 2V
So `((E_(1))/(500+X)) X = 2 `
`rArr ((12)/(500+X))X =2`
`rArr 12X=1000+2X`
`rArr 10X =1000" " X=100Omega`
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