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A galvanometer of resistance 50Omega is ...

A galvanometer of resistance `50Omega` is converted into an ammeter by connecting a low resistance (shunt) of value `1Omega` in parallel to the galvanometer, S. If full - scale deflection current of the galvanometer is 10 mA, then the maximum current that can be measured by the ammeter is -

A

500 mA

B

510 mA

C

610 mA

D

490 mA

Text Solution

Verified by Experts

The correct Answer is:
B
`S="G"(I_(g))/(I-I_(g))`

`I=50xx(10)/(I-10)`
`I-10=500`
`I=510mA`
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