The time period of oscillation of a body is given by `T=2pisqrt((mgA)/(K))`
K: Represents the kinetic energy, m mass, g acceleration due to gravity and A is unknown If `[A]=M^(x)L^(y)T^(z)`, then what is the value of x+y+z?

The time period of an oscillating body is given by T=2pisqrt((m)/(adg)) . What is the force equation for this body?

The time period of a simple pendulum is given by T = 2pi sqrt((l)/(g)) where 'l' is the length of the pendulum and 'g' is the acceleration due to gravity at that place. (a) Express 'g' in terms of T (b) What is the length of the seconds pendulum ? (Take g = 10 m s^(-2) )

Find the dimensions of K in the relation T = 2pi sqrt((KI^2g)/(mG)) where T is time period, I is length, m is mass, g is acceleration due to gravity and G is gravitational constant.

The displacement of a body is given by s=(1)/(2)g t^(2) where g is acceleration due to gravity. The velocity of the body at any time t is

If the time period of a simple pendulum is T = 2pi sqrt(l//g) , then the fractional error in acceleration due to gravity is

The time period of a compound pendulum is given by T=2pisqrt((I)/(mgl)) {:(,"where","I=moment of inertia about the centre of the suspension,"),(,,"g=acceleration due to gravity , m=mass of the pendulam"),(,,"l=distance of the centre of the gravity from the centre of the suspension."):}

Time period T of a simple pendulum of length l is given by T = 2pisqrt((l)/(g)) . If the length is increased by 2% then an approximate change in the time period is