A gaseous hydrocarbon when burns in oxygen gives `3.38g` `CO_(2)`, `0.690g` water and no other product.At STP,volume of `10L` of this hydrocarbon is found to weigh `11.6g` .What will be the molecular mass of the hydrocarbon.

A gaseous hydrocarbon on complete combustion gives 3.38 g of CO_(2) and 0.690 g of H_(2)O and no other product. The empirical formula of the hydrocarbon is

If the mass of 10^22 molecules of a hydrocarbon is about 1.2 g, then the gram molecular mass of hydrocarbon is :

A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 L (measured at S.T.P.) of this welding gas is found to weigh 11.6 g. Calculate (i) empirical fomula (ii) molar mass of the gas, and (iii) molecular formula.

A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 litre (Measured at STP) of this welding gas is found weigh 11.6 g . Calculate (i) empirical formula, (ii) molar mass of the gas, and (iii) molecular formula.

A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gas 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 L (measured at STP) of this welding gas is found to weigh 11.6 g. Calcuate

25 g hydrocarbon of burning with excess of air produces 88 g CO_(2) and 9g water, mass of C and H in the hydrocarbon is

A hydrocarbon contains 10.5 g of carbon per gram of hydrogen. 1 L of vapour of the hydrocarbon at 127^(@)C and 1 atm pressure weighs 2.8 g . Find the molecular formula of the hydrocarbon.