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If A={1, 2, 3}, then the relation R={...

If A={1, 2, 3}, then the relation
`R={(1,1),(2,2),(3,1),(1,3)}`, is

A

reflexive

B

symmetric

C

transitive

D

equivalence

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The correct Answer is:
To determine the properties of the relation \( R = \{(1,1), (2,2), (3,1), (1,3)\} \) with respect to the set \( A = \{1, 2, 3\} \), we will check if the relation is reflexive, symmetric, transitive, or equivalent. ### Step 1: Check for Reflexivity A relation is reflexive if every element in the set \( A \) is related to itself. This means that for every \( a \in A \), the pair \( (a,a) \) must be in \( R \). - For \( 1 \): \( (1,1) \) is in \( R \). - For \( 2 \): \( (2,2) \) is in \( R \). - For \( 3 \): \( (3,3) \) is **not** in \( R \). Since \( (3,3) \) is not present in \( R \), the relation is **not reflexive**. ### Step 2: Check for Symmetry A relation is symmetric if for every pair \( (a,b) \in R \), the pair \( (b,a) \) must also be in \( R \). - For \( (1,1) \): \( (1,1) \) is in \( R \) (symmetric). - For \( (2,2) \): \( (2,2) \) is in \( R \) (symmetric). - For \( (3,1) \): \( (1,3) \) is in \( R \) (symmetric). - For \( (1,3) \): \( (3,1) \) is **not** in \( R \). Since \( (3,1) \) does not have its symmetric counterpart \( (1,3) \) in \( R \), the relation is **not symmetric**. ### Step 3: Check for Transitivity A relation is transitive if whenever \( (a,b) \in R \) and \( (b,c) \in R \), then \( (a,c) \) must also be in \( R \). - Check pairs: - \( (1,1) \) and \( (1,3) \) implies \( (1,3) \) is in \( R \) (true). - \( (1,3) \) and \( (3,1) \) implies \( (1,1) \) is in \( R \) (true). - \( (3,1) \) and \( (1,1) \) implies \( (3,1) \) is in \( R \) (true). However, we need to check all combinations: - There are no pairs \( (a,b) \) and \( (b,c) \) that lead to a contradiction. Since all conditions are satisfied, the relation is **transitive**. ### Step 4: Check for Equivalence A relation is equivalent if it is reflexive, symmetric, and transitive. Since we found that the relation is not reflexive and not symmetric, it cannot be equivalent. ### Conclusion The relation \( R \) is: - Not Reflexive - Not Symmetric - Transitive - Not Equivalent
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