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If the rate of change of area of a circl...

If the rate of change of area of a circle is equal to the rate of change of its diameter, then its radius is equal to (a) unit (b) unit (c) units (d) units

A

`(2)/(pi)` unit

B

`(1)/(pi)` unit

C

`(pi)/(2)` units

D

`pi` units

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The correct Answer is:
To solve the problem, we need to find the radius of a circle when the rate of change of its area is equal to the rate of change of its diameter. Let's go through the steps systematically. ### Step 1: Understand the formulas The area \( A \) of a circle is given by the formula: \[ A = \pi r^2 \] where \( r \) is the radius of the circle. The diameter \( d \) of the circle is related to the radius by: \[ d = 2r \] ### Step 2: Differentiate the area with respect to time To find the rate of change of the area with respect to time, we differentiate \( A \) with respect to \( t \): \[ \frac{dA}{dt} = \frac{d}{dt}(\pi r^2) = 2\pi r \frac{dr}{dt} \] ### Step 3: Differentiate the diameter with respect to time Now, we differentiate the diameter with respect to time: \[ \frac{dd}{dt} = \frac{d}{dt}(2r) = 2\frac{dr}{dt} \] ### Step 4: Set the rates equal to each other According to the problem, the rate of change of the area is equal to the rate of change of the diameter: \[ \frac{dA}{dt} = \frac{dd}{dt} \] Substituting the expressions we derived: \[ 2\pi r \frac{dr}{dt} = 2\frac{dr}{dt} \] ### Step 5: Simplify the equation Assuming \( \frac{dr}{dt} \neq 0 \) (since if it were zero, the rates would not be changing), we can divide both sides by \( 2\frac{dr}{dt} \): \[ \pi r = 1 \] ### Step 6: Solve for the radius Now, we can solve for \( r \): \[ r = \frac{1}{\pi} \] ### Conclusion The radius of the circle when the rate of change of area is equal to the rate of change of its diameter is: \[ r = \frac{1}{\pi} \text{ units} \] ### Final Answer Thus, the correct option is: (c) \( \frac{1}{\pi} \text{ units} \) ---

To solve the problem, we need to find the radius of a circle when the rate of change of its area is equal to the rate of change of its diameter. Let's go through the steps systematically. ### Step 1: Understand the formulas The area \( A \) of a circle is given by the formula: \[ A = \pi r^2 \] where \( r \) is the radius of the circle. ...
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OBJECTIVE RD SHARMA ENGLISH-DERIVATIVE AS A RATE MEASURER -Exercise
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  2. The edge of a cube is equal to the radius of a sphere. If the edge and...

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  3. If the velocity v of a particle moving along a straight line and its d...

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  4. If the rate of change of sine of an angle theta is k, then the rate of...

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  5. If a particle moves according to the law s=6t^(2)-(t^(3))/(2), then th...

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  6. A particle moves on a line according to the law s=at^(2)+bt+c. If the ...

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  7. If a particle moving along a line follows the law t=as^(2)+bs+c, then...

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  8. If the semivertical angle of a cone is 45^@. Then the rate of change o...

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  9. On the curve x^3=12 y , find the interval of values of x for which the...

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  10. If the rate of change of area of a square plate is equal to that of th...

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  11. A stone dropped into a quiet lake. If the waves moves in circles at th...

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  12. The side of a square is equal to the diameter of a circle. If the side...

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  13. A variable DeltaABC is inscribed in a circle of diameter x units. At a...

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  14. The radius and height of a cylinder are equal. If the radius of the sp...

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  15. The points on the curve 12y = x^(3) whose ordinate and abscissa change...

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  16. A particle moves along the parabola y^2=2ax in such a way that its pro...

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  17. The diameter of a circle is increasing at the rate of 1 cm/sec. When i...

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  18. A man 2 metres tall walks away from a lamp post 5 metres height at the...

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  19. At an instant the diagonal of a square is increasing at the rate of 0...

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  20. If s=ae^(t) + be^(-t) is the equation of motion of a particle, then it...

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  21. A circular metal plate is heated so that its radius increases at a rat...

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