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By shifting origin to (-1,2) the equatio...

By shifting origin to `(-1,2)` the equation `y^2+8x - 4y + 12 = 0` changes as `Y^2 = 4aX` then `a=`

A

1

B

2

C

`-2`

D

`-1`

Text Solution

Verified by Experts

The correct Answer is:
C

By shifting the origin at (1,2) we have
`x=X+1,y=Y+2`
Substituting these values in `y^(2)-8x-4y+12=0` we have
`(Y+2)^(2)-8h(X+1)-4(Y+2)+12=0`
`rArr Y^(2)-8X=0 rArr Y^(2)=8X`
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