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If [x] denote the greatest integer less than or equal to x then in order that the set of equations `2x - 2y = 4, 7x -3 y = 2, [3pi[ x - [e] y = [4a]` may be consistent then 'a' should lie in

A

`[3, 7//2)`

B

`(3, 7//3)`

C

`(3, 7//3]`

D

none of these

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The correct Answer is:
To solve the problem step by step, we will analyze the given equations and find the conditions for 'a' such that the system of equations is consistent. ### Step-by-Step Solution: 1. **Write down the equations:** The given equations are: \[ 2x - 2y = 4 \quad \text{(1)} \] \[ 7x - 3y = 2 \quad \text{(2)} \] \[ [3\pi] x - [e] y = [4a] \quad \text{(3)} \] 2. **Solve the first two equations for x and y:** From equation (1): \[ 2x - 2y = 4 \implies x - y = 2 \implies y = x - 2 \quad \text{(4)} \] Substitute (4) into equation (2): \[ 7x - 3(x - 2) = 2 \] Simplifying this: \[ 7x - 3x + 6 = 2 \implies 4x + 6 = 2 \implies 4x = 2 - 6 \implies 4x = -4 \implies x = -1 \] Now substitute \( x = -1 \) back into (4) to find y: \[ y = -1 - 2 = -3 \] 3. **Substitute x and y into the third equation:** Now we substitute \( x = -1 \) and \( y = -3 \) into equation (3): \[ [3\pi](-1) - [e](-3) = [4a] \] We need to find the greatest integer values of \( [3\pi] \) and \( [e] \). - The value of \( \pi \) is approximately \( 3.14 \), so \( 3\pi \approx 9.42 \) and thus \( [3\pi] = 9 \). - The value of \( e \) is approximately \( 2.71 \), so \( [e] = 2 \). Now substituting these values: \[ 9(-1) - 2(-3) = [4a] \] This simplifies to: \[ -9 + 6 = [4a] \implies -3 = [4a] \] 4. **Determine the range for 'a':** Since \( [4a] = -3 \), this means: \[ -3 \leq 4a < -2 \] Dividing the entire inequality by 4: \[ -\frac{3}{4} \leq a < -\frac{1}{2} \] 5. **Final answer:** Therefore, the value of 'a' should lie in the range: \[ a \in \left[-\frac{3}{4}, -\frac{1}{2}\right) \]
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  6. Delta = |(1//a,1,bc),(1//b,1,ca),(1//c,1,ab)|=

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  8. If abc!=0 then |{:(1+a,1,1),(1,1+b,1),(1,1,1+c):}| is

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  10. If a, b and c are all different from zero and Delta = |(1 +a,1,1),(1...

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