How many different nine-digit numbers can be formed from the digits of the number 223355888 by rearrangement of the digits so that the odd digits occupy even places:

Options

A. 16
B. 36
C. 60
D. 180

Explanation

There are 4 odd digits viz. 3, 3, 5, 5 and 4 even places. So, odd digits can occupy even in `(4!)/(2!2!)` ways.
`:.` Required number of 9 digit numbers `=(4!)/(2!2!)xx(5!)/(2!3!)=60`.