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Find the number of ways in which 10 cond...

Find the number of ways in which 10 condidates `A_(1),A_(2),......,A_(10)` can be ranked so that `A_(1)` is always above `A_(2)`,

A

10!

B

`(10!)/(2)`

C

9!

D

none of these

Text Solution

Verified by Experts

Ten candidates can be ranked in 10! ways. In half of these ways A1 is above `A_(2)` and in another half `A_(2)` is above `A_(1)`. So, required number of ways `=(10!)/(2)`
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