The number of ways in which we can distribute `m n` students equally among `m` sections is given by a. `((m n !))/(n !)` b. `((m n)!)/((n !)6m)` c. `((m n)!)/(m ! n !)` d. `(m n^m)`

Options

A. `((mn)!)/(n!)`
B. `((mn)!)/((n!)^(m))`
C. `((mn)!)/(m!n!)`
D. `((2n)!)/((n!)^(2))`

Explanation

Here, the ordering of sections is important.
So, required number of ways `=(((mn)!)/((n!)^(m)m!))m!""=((mn)!)/((n!)^(m))`