Home
Class 11
MATHS
If x,y,z is integer and xge0,yge1,zge2,...

If x,y,z is integer and `xge0,yge1,zge2,x+y+z=15` then the number of values of the ordered triplet (x,y,z) is

A

91

B

455

C

`""^(17)C_(15)`

D

none of these

Text Solution

Verified by Experts

Let `y'=y-1andz'=z-2`. Then,
x+y+z=15
`impliesx+y'+z'=12` where `xge0,y'ge0andz'ge0`
The total number of solutions of this equations is
`""^(12+3-1)C_(3-1)=""^(14)C_(2)`
Hence, required number of ordered triplets (x, y, z) is
`""^(14)C_(2)=91`.
Promotional Banner

Topper's Solved these Questions

  • PERMUTATIONS AND COMBINATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section II - Assertion Reason Type|9 Videos
  • PERMUTATIONS AND COMBINATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Exercise|136 Videos
  • PERMUTATIONS AND COMBINATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|60 Videos
  • PARABOLA

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|30 Videos
  • PROBABILITY

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|45 Videos

Similar Questions

Explore conceptually related problems

If x, y, z are integers such that x >=0, y >=1, z >=2 and x + y + z = 15 , then the number of values of ordered triplets (x,y,z) are

If xyz = 1 and x, y, z gt 0 then the minimum value of the expression (x+2y)(y+2z)(z+2x) is

The equation "cosec " x/2 + " cosec " y/2 + " cosec " z/2=6 , where 0 lt x, y,z lt pi/2 and x+y+z=pi , have i) Three Ordered triplet (x,y,z)solutions ii) Two ordered triplet (x,y,z) solutions. iii) Just one ordered triplet (x,y,z) solution iv) No ordered triplet (x,y,z) solution

If x , y , z are natural numbers such that cot^(-1)x+cot^(-1)y=cot^(-1)z then the number of ordered triplets (x , y , z) that satisfy the equation is 0 (b) 1 (c) 2 (d) Infinite solutions

If x,y,z are positive integers, then the value of the expression (x+y)(y+z)(z+x) is

If 9(27)^(x^2+y+z)+9(27)^(x+y+z^2)+9(27)^(x+y^2+z)=11 then find the number of possible triplet (x ,y ,z)dot

If x > 0, y > 0, z>0 and x + y + z = 1 then the minimum value of x/(2-x)+y/(2-y)+z/(2-z) is:

If x,y and z are positive integers such that x < y < z and x + y + z = 6 , then what is the value of z?

Find the value of the "determinant" |{:(1,x,y+z),(1,y,z+x),(1,z,x+y):}|

If x, y, z are distinct positive numbers such that x+(1)/(y)=y+(1)/(z)=z+(1)/(x) , then the value of xyz is __________

OBJECTIVE RD SHARMA ENGLISH-PERMUTATIONS AND COMBINATIONS-Section I - Solved Mcqs
  1. In how many ways can 30 marks be allotted to 8 question if each que...

    Text Solution

    |

  2. The number of points in space, whose each co-ordinate is a negative in...

    Text Solution

    |

  3. If x,y,z is integer and xge0,yge1,zge2,x+y+z=15 then the number of va...

    Text Solution

    |

  4. If a, b, c, are natural numbers in AP and then the possible number of...

    Text Solution

    |

  5. If x, y, z, t are odd natural numbers such that x + y + z +w=20 then ...

    Text Solution

    |

  6. The number of ways in which a score of 11 can be made from a through t...

    Text Solution

    |

  7. The sum of all the numbers of four different digits that can be mad...

    Text Solution

    |

  8. There are 5 mangoes, 3 oranges and 4 bananas. The number of ways of se...

    Text Solution

    |

  9. There are 4 mangoes, 3 apples, 2 oranges and 1 each of 3 other varieti...

    Text Solution

    |

  10. The number of divisor of 4200, is

    Text Solution

    |

  11. The number of proper divisors of 2520, is

    Text Solution

    |

  12. The number of porper divisors of 2^(m)xx6^(n)xx15^(p) , is

    Text Solution

    |

  13. The number of proper divisors of 1800, which are also divisible by 10,...

    Text Solution

    |

  14. The number of even proper divisors of 5040, is

    Text Solution

    |

  15. The number of odd proper divisors of 5040, is

    Text Solution

    |

  16. Find the number of odd proper divisors of 3^pxx6^mxx21^ndot

    Text Solution

    |

  17. The number of divisors of the form 4K + 2 , K ge 0 of the integers 24...

    Text Solution

    |

  18. The number of divisors of 2^4 .3^3 .5^2, having two prime factors, is

    Text Solution

    |

  19. There are five balls of different colours and five boxes of colours sa...

    Text Solution

    |

  20. The number of 5-digit numbers in which no two consecutive digits are i...

    Text Solution

    |