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The number of divisors of the form 4K + ...

The number of divisors of the form `4K + 2 , K ge 0` of the integers 240 is

A

4

B

8

C

10

D

3

Text Solution

Verified by Experts

The correct Answer is:
A
We have, `240=2^(4)xx3xx5`
and, `4n+2=2(2n+1)=2xx` An odd natural number
Hence, number of divisors of the form 4n+2
= Number of ways of selecting one 2 out of four 2's and any number of 3's and 5's
`=1xx(1+1)xx(1+1)=4`.
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