Home
Class 11
MATHS
There are n different books and p copies...

There are n different books and p copies of each in a library. The number of ways in which one or more books can be selected is:

A

`m^(n)+1`

B

`(m+1)^(n)-1`

C

`(n+1)^(n)-m`

D

m

Text Solution

Verified by Experts

The correct Answer is:
B
There are (m+1) choices for each of n different boods. So, the total number of choices is `(m+1)^(n)` including one choice in which we do not select any book.
Hence, the required number of ways `=(m+1)^(n)-1`.
Promotional Banner

Topper's Solved these Questions

  • PERMUTATIONS AND COMBINATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section II - Assertion Reason Type|9 Videos

  • PERMUTATIONS AND COMBINATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Exercise|136 Videos

  • PERMUTATIONS AND COMBINATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|60 Videos

  • PARABOLA

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|30 Videos

  • PROBABILITY

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|45 Videos

Similar Questions

Explore conceptually related problems

There are m copies each ofn different books in a university library. The number of ways in which one or more than one book can be selected is

There are 10 different books in a shelf. The number of ways in which three books can be selected so that exactly two of them are consecutive is

A shopkeeper has 11 copies each of nine different books, then the number of ways in which atleast one book can be selected is

There are p copies each of n different books. Find the number of ways in which a nonempty selection can be made from them.

There are p copies each of n different books. Find the number of ways in which a nonempty selection can be made from them.

A library has a copies of one book, b copies each of two books, c copies each of three books, a single copy of d books. The total number of ways in which these books can be arranged in a shelf is equal to a. ((a+2b+3c+d)!)/(a !(b !)^2(c !)^3) b. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^3) c. ((a+b+3c+d)!)/((c !)^3) d. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^)

A library has a copies of one book, b copies each of two books, c copies each of three books, a single copy of d books. The total number of ways in which these books can be arranged in a shelf is equal to a. ((a+2b+3c+d)!)/(a !(b !)^2(c !)^3) b. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^3) c. ((a+b+3c+d)!)/((c !)^3) d. ((a+2b+3c+d)!)/(a !(2b !)^(c !)^)

There are n different books each having m copies . If the total number of ways of making a selection from them is 255 and m-n+1=0 then distance of point (m,n) from the origin (A) 3 (B) 4 (C) 5 (D) none of these

The number of ways to distribute m xx n different thing among n persons equally = ((mn)!)/((m!)^(n)) The number of ways in which 12 different books can be divided equally in 3 heaps of book is

There are p copies each of n different subjects. Find the number of ways in which a nonempty selection can be made from them. Also find the number of ways in which at least one copy of each subject is selected.

OBJECTIVE RD SHARMA ENGLISH-PERMUTATIONS AND COMBINATIONS-Section I - Solved Mcqs
  1. Find the number of ways to give 16 different things to three persons A...

    Text Solution

    |

  2. If P(1), P(2), P(3), ……, P(m+1) are distinct prime numbers. Then the...

    Text Solution

    |

  3. There are n different books and p copies of each in a library. The num...

    Text Solution

    |

  4. The number of ways in which one or more balls can be selected out of 1...

    Text Solution

    |

  5. The number of all three element subsets of the set {a(1),a(2),a(3).......

    Text Solution

    |

  6. If one quarter of all three element subsete of the set A={a(1),a(2),a(...

    Text Solution

    |

  7. The sum of the divisors of 2^(5)*3^(4)*5^(2) is

    Text Solution

    |

  8. The number of words that can be made by writing down the letters of th...

    Text Solution

    |

  9. Find the number of ways in which n different prizes can be distributed...

    Text Solution

    |

  10. The total number of positive integral solutions for (x, y, z) such tha...

    Text Solution

    |

  11. The total number of positive integral solutions of abc=30, is

    Text Solution

    |

  12. The total numbre of intergral solutins of abc =24, is

    Text Solution

    |

  13. A bag contains 3 black, 4 white and 2 red balls, all the balls being d...

    Text Solution

    |

  14. The number of different pairs of words (,) that can be made with the l...

    Text Solution

    |

  15. In the decimal system of numeration the number of 6-digit numbers in w...

    Text Solution

    |

  16. There are 60 questions in a question paper. If no two students solve t...

    Text Solution

    |

  17. An n-digit number is a positive number with exactly n digits. Ni...

    Text Solution

    |

  18. How many ways are there to arrange the letters in the word GARDEN with...

    Text Solution

    |

  19. The number of ways of distributing 8 identical balls in 3 distinct box...

    Text Solution

    |

  20. The number of seven-digit numbers, with sum of the digits equal to 10 ...

    Text Solution

    |