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Every two persons shakes hands with eac...

Every two persons shakes hands with each other in a party and the total number of handis 66. The number of guests in the party is

A

11

B

12

C

13

D

14

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The correct Answer is:
To solve the problem of finding the number of guests in a party where every two persons shake hands and the total number of handshakes is 66, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: - We know that every two persons shake hands. If there are \( n \) guests, the total number of handshakes can be calculated using the combination formula \( C(n, 2) \), which is given by: \[ C(n, 2) = \frac{n(n-1)}{2} \] - According to the problem, the total number of handshakes is 66. 2. **Setting Up the Equation**: - We can set up the equation based on the information given: \[ \frac{n(n-1)}{2} = 66 \] 3. **Eliminating the Fraction**: - To eliminate the fraction, multiply both sides of the equation by 2: \[ n(n-1) = 132 \] 4. **Rearranging the Equation**: - Rearranging gives us a quadratic equation: \[ n^2 - n - 132 = 0 \] 5. **Factoring the Quadratic**: - We can factor the quadratic equation: \[ n^2 - 12n + 11n - 132 = 0 \] - This can be factored as: \[ (n - 12)(n + 11) = 0 \] 6. **Finding the Roots**: - Setting each factor to zero gives us: \[ n - 12 = 0 \quad \text{or} \quad n + 11 = 0 \] - Thus, we find: \[ n = 12 \quad \text{or} \quad n = -11 \] 7. **Interpreting the Results**: - Since the number of guests cannot be negative, we discard \( n = -11 \). - Therefore, the number of guests in the party is: \[ n = 12 \] ### Final Answer: The number of guests in the party is **12**.
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