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If 7 points out of 12 are in the same st...

If 7 points out of 12 are in the same straight line, then the number of triangles formed is

A

19

B

158

C

185

D

201

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The correct Answer is:
To find the number of triangles that can be formed from 12 points, where 7 of those points are collinear (on the same straight line), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: We need to form triangles using 12 points, but we have to consider that 7 of these points are collinear. A triangle cannot be formed using 3 collinear points. 2. **Total Ways to Choose 3 Points**: First, we calculate the total number of ways to choose any 3 points from the 12 points. This can be calculated using the combination formula: \[ \text{Total ways} = \binom{12}{3} \] The formula for combinations is given by: \[ \binom{n}{r} = \frac{n!}{r!(n-r)!} \] 3. **Calculating \(\binom{12}{3}\)**: \[ \binom{12}{3} = \frac{12!}{3!(12-3)!} = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = \frac{1320}{6} = 220 \] 4. **Ways to Choose 3 Collinear Points**: Next, we calculate the number of ways to choose 3 points from the 7 collinear points, which cannot form a triangle: \[ \text{Collinear ways} = \binom{7}{3} \] 5. **Calculating \(\binom{7}{3}\)**: \[ \binom{7}{3} = \frac{7!}{3!(7-3)!} = \frac{7!}{3! \cdot 4!} = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} = \frac{210}{6} = 35 \] 6. **Finding Valid Triangles**: Now, we subtract the number of ways to choose 3 collinear points from the total ways to choose 3 points: \[ \text{Valid triangles} = \binom{12}{3} - \binom{7}{3} = 220 - 35 = 185 \] 7. **Conclusion**: Therefore, the number of triangles that can be formed from the 12 points, considering that 7 points are collinear, is: \[ \text{Number of triangles} = 185 \] ### Final Answer: The number of triangles formed is **185**.
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