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The number of words which can be formed ...

The number of words which can be formed out of the letters `a`, `b`, `c`, `d`, `e` `f` taken 3 together, each word containing one vowel at least is

A

72

B

48

C

96

D

none of these

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AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of words that can be formed from the letters `a`, `b`, `c`, `d`, `e`, and `f` taken 3 at a time, with the condition that each word must contain at least one vowel, we can break it down into steps: ### Step 1: Identify the letters and categorize them We have the letters: `a`, `b`, `c`, `d`, `e`, `f`. - Vowels: `a`, `e` (2 vowels) - Consonants: `b`, `c`, `d`, `f` (4 consonants) ### Step 2: Determine the cases based on the number of vowels Since we need at least one vowel in each word, we can have two cases: 1. Case 1: 1 vowel and 2 consonants 2. Case 2: 2 vowels and 1 consonant ### Step 3: Calculate the number of arrangements for Case 1 (1 vowel and 2 consonants) - **Choosing 1 vowel from 2 vowels**: This can be done in \( \binom{2}{1} = 2 \) ways. - **Choosing 2 consonants from 4 consonants**: This can be done in \( \binom{4}{2} = 6 \) ways. - **Arranging the 3 letters (1 vowel + 2 consonants)**: The arrangement can be done in \( 3! = 6 \) ways. So, the total for Case 1 is: \[ \text{Total for Case 1} = \binom{2}{1} \times \binom{4}{2} \times 3! = 2 \times 6 \times 6 = 72 \] ### Step 4: Calculate the number of arrangements for Case 2 (2 vowels and 1 consonant) - **Choosing 2 vowels from 2 vowels**: This can be done in \( \binom{2}{2} = 1 \) way. - **Choosing 1 consonant from 4 consonants**: This can be done in \( \binom{4}{1} = 4 \) ways. - **Arranging the 3 letters (2 vowels + 1 consonant)**: The arrangement can be done in \( 3! = 6 \) ways. So, the total for Case 2 is: \[ \text{Total for Case 2} = \binom{2}{2} \times \binom{4}{1} \times 3! = 1 \times 4 \times 6 = 24 \] ### Step 5: Combine the results from both cases Now, we add the totals from both cases to get the final answer: \[ \text{Total number of words} = \text{Total for Case 1} + \text{Total for Case 2} = 72 + 24 = 96 \] ### Final Answer The total number of words that can be formed is **96**. ---
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