In a steamer there are stalls for 12 animals and there are cows, horses and calves (not less than 12 of each) ready to be shipped, the total number of ways in which the shipload can be made, is

Options

A. `3^(12)`
B. `12^(3)`
C. `""^(12)P_(3)`
D. `""^(12)C_(3)`

Answer

To solve the problem, we need to determine the total number of ways to fill 12 stalls with cows, horses, and calves, given that there are at least 12 of each type of animal available.

### Step-by-Step Solution:

1. **Identify the Number of Stalls and Choices**:
- We have 12 stalls available for the animals.
- For each stall, we have three options: we can place a cow, a horse, or a calf.

2. **Choices for Each Stall**:
- Since each stall can independently have one of the three animals, the choice for each stall is independent of the others.

3. **Calculate Total Combinations**:
- For the first stall, we have 3 choices (cow, horse, or calf).
- For the second stall, we also have 3 choices.
- This pattern continues for all 12 stalls.

4. **Using the Multiplication Principle**:
- Since the choices are independent, we multiply the number of choices for each stall.
- Therefore, the total number of ways to fill the stalls is:
\[ 3 \times 3 \times 3 \times \ldots \text{ (12 times)} = 3^{12} \]

5. **Final Calculation**:
- The total number of ways to fill the 12 stalls with cows, horses, and calves is \( 3^{12} \).

### Conclusion:
The total number of ways in which the shipload can be made is \( 3^{12} \).