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The greatest possible number of points of intersection of 8 straight lines and 4 circles is:

A

32

B

64

C

76

D

104

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The correct Answer is:
To find the greatest possible number of points of intersection of 8 straight lines and 4 circles, we will break down the problem into three cases: intersections between lines, intersections between circles, and intersections between lines and circles. ### Step-by-Step Solution: **Step 1: Intersections between Lines** - The maximum number of intersection points formed by \( n \) lines is given by the formula: \[ \text{Number of intersections} = \binom{n}{2} \] - For 8 lines, we calculate: \[ \binom{8}{2} = \frac{8 \times 7}{2} = 28 \] **Step 2: Intersections between Circles** - The maximum number of intersection points formed by \( m \) circles is given by the formula: \[ \text{Number of intersections} = \binom{m}{2} \times 2 \] - For 4 circles, we calculate: \[ \binom{4}{2} = \frac{4 \times 3}{2} = 6 \] - Since each pair of circles can intersect at 2 points: \[ \text{Total intersections from circles} = 6 \times 2 = 12 \] **Step 3: Intersections between Lines and Circles** - Each line can intersect with each circle at 2 points. Therefore, the total number of intersections between lines and circles is: \[ \text{Total intersections} = \text{Number of lines} \times \text{Number of circles} \times 2 \] - For 8 lines and 4 circles: \[ \text{Total intersections} = 8 \times 4 \times 2 = 64 \] **Step 4: Total Points of Intersection** - Now, we sum all the points of intersection from the three cases: \[ \text{Total points of intersection} = \text{Intersections from lines} + \text{Intersections from circles} + \text{Intersections from lines and circles} \] - Plugging in the values: \[ \text{Total points of intersection} = 28 + 12 + 64 = 104 \] ### Final Answer: The greatest possible number of points of intersection of 8 straight lines and 4 circles is **104**. ---
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