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How many numbers between 5000 and 10,000...

How many numbers between 5000 and 10,000 can be formed using the digits 1,2,3,4,5,6,7,8,9, each digit appearing not more than once in each number?

A

`5xx""^(8)P_(3)`

B

`5xx""^(8)C_(8)`

C

`5!xx""^(8)P_(3)`

D

`5!xx""^(8)C_(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many numbers between 5000 and 10,000 can be formed using the digits 1, 2, 3, 4, 5, 6, 7, 8, and 9 (with each digit appearing not more than once), we can follow these steps: ### Step 1: Determine the range of numbers We need to find four-digit numbers that lie between 5000 and 10,000. Therefore, the first digit must be 5, 6, 7, 8, or 9. ### Step 2: Choose the first digit The first digit can be any of the following: 5, 6, 7, 8, or 9. This gives us **5 options** for the first digit. ### Step 3: Choose the second digit After choosing the first digit, we cannot use that digit again. Since we initially have 9 digits (1 to 9), after using one digit for the first position, we are left with 8 remaining digits. Therefore, we have **8 options** for the second digit. ### Step 4: Choose the third digit Similarly, after selecting the first and second digits, we have used 2 digits. This leaves us with 7 digits available to choose from for the third position. Hence, we have **7 options** for the third digit. ### Step 5: Choose the fourth digit Finally, after selecting the first three digits, we have used 3 digits, leaving us with 6 remaining digits. Thus, we have **6 options** for the fourth digit. ### Step 6: Calculate the total combinations Now, we can calculate the total number of four-digit numbers that can be formed: \[ \text{Total Numbers} = (\text{Choices for 1st digit}) \times (\text{Choices for 2nd digit}) \times (\text{Choices for 3rd digit}) \times (\text{Choices for 4th digit}) \] \[ \text{Total Numbers} = 5 \times 8 \times 7 \times 6 \] ### Step 7: Perform the multiplication Calculating the above expression: \[ 5 \times 8 = 40 \] \[ 40 \times 7 = 280 \] \[ 280 \times 6 = 1680 \] Thus, the total number of four-digit numbers that can be formed between 5000 and 10,000 using the digits 1 to 9, with no repetitions, is **1680**. ### Final Answer The total number of numbers between 5000 and 10,000 that can be formed is **1680**. ---
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