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If Pm stands for ^m Pm , then prove that...

If `P_m` stands for `^m P_m` , then prove that: `1+1. P_1+2. P_2+3. P_3++ndotP_n=(n+1)!`

A

`(n-1!)`

B

n!

C

`(n+1)!-1`

D

none of these

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OBJECTIVE RD SHARMA ENGLISH-PERMUTATIONS AND COMBINATIONS-Chapter Test
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