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There are n-points (ngt2) in each to two...

There are n-points `(ngt2)` in each to two parallel lines. Every point on one line is joined to every point on the other line by a line segment drawn within the lines. The number of point (between the lines) in which these segments intersect, is

A

`""^(2n)C_(2)-2.""^(n)C_(1)+2`

B

`""^(2n)C_(2)-2xx""^(n)C_(2)`

C

`""^(n)C_(2)xx""^(n)C_(2)`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the number of intersection points formed by line segments connecting points on two parallel lines. Let's break down the solution step by step. ### Step 1: Understanding the Setup We have two parallel lines, each containing \( n \) points. We will denote the points on the first line as \( A_1, A_2, \ldots, A_n \) and the points on the second line as \( B_1, B_2, \ldots, B_n \). ### Step 2: Connecting the Points Each point on the first line is connected to every point on the second line by a line segment. This means that for every point \( A_i \) on the first line, there are \( n \) segments connecting it to each of the \( B_j \) points on the second line. ### Step 3: Identifying Intersection Points An intersection occurs between two segments \( A_iB_j \) and \( A_kB_l \) if and only if the points are chosen such that: - \( i < k \) and \( j > l \) or - \( i > k \) and \( j < l \) This means that to create an intersection, we need to choose two points from each line. ### Step 4: Choosing Points To find the number of ways to select two points from each line, we can use combinations. The number of ways to choose 2 points from \( n \) points is given by \( \binom{n}{2} \). ### Step 5: Total Intersections Since we can choose any two points from the first line and any two points from the second line, the total number of intersection points is given by: \[ \text{Total Intersections} = \binom{n}{2} \times \binom{n}{2} \] This simplifies to: \[ \text{Total Intersections} = \left( \binom{n}{2} \right)^2 \] ### Step 6: Final Expression The final expression for the number of intersection points between the segments is: \[ \left( \frac{n(n-1)}{2} \right)^2 = \frac{n^2(n-1)^2}{4} \] ### Conclusion Thus, the number of points between the lines where the segments intersect is \( \binom{n}{2}^2 \).
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