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The number of ways in which 9 persons ca...

The number of ways in which 9 persons can be divided into three equal groups is

A

1680

B

840

C

560

D

280

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The correct Answer is:
To find the number of ways to divide 9 persons into three equal groups, we can follow these steps: ### Step-by-Step Solution: 1. **Choose the first group of 3 persons from 9**: We can select 3 persons out of 9. This can be calculated using the combination formula \( \binom{n}{r} \), where \( n \) is the total number of persons and \( r \) is the number of persons to choose. \[ \text{Ways to choose the first group} = \binom{9}{3} \] 2. **Choose the second group of 3 persons from the remaining 6**: After selecting the first group, we have 6 persons left. We can choose another group of 3 persons from these 6. \[ \text{Ways to choose the second group} = \binom{6}{3} \] 3. **Choose the third group of 3 persons from the remaining 3**: After selecting the first two groups, there are 3 persons left. We can choose all of them to form the third group. \[ \text{Ways to choose the third group} = \binom{3}{3} \] 4. **Calculate the total combinations**: The total number of ways to form the groups is the product of the combinations calculated in the previous steps: \[ \text{Total ways} = \binom{9}{3} \times \binom{6}{3} \times \binom{3}{3} \] 5. **Adjust for indistinguishable groups**: Since the groups are indistinguishable (the order of the groups does not matter), we need to divide by the number of ways to arrange the 3 groups, which is \( 3! \): \[ \text{Final count} = \frac{\binom{9}{3} \times \binom{6}{3} \times \binom{3}{3}}{3!} \] 6. **Calculate the values**: - \( \binom{9}{3} = \frac{9!}{3!(9-3)!} = \frac{9 \times 8 \times 7}{3 \times 2 \times 1} = 84 \) - \( \binom{6}{3} = \frac{6!}{3!(6-3)!} = \frac{6 \times 5 \times 4}{3 \times 2 \times 1} = 20 \) - \( \binom{3}{3} = 1 \) - Therefore, total ways = \( 84 \times 20 \times 1 = 1680 \) - Now divide by \( 3! = 6 \): \[ \text{Final count} = \frac{1680}{6} = 280 \] ### Final Answer: The number of ways in which 9 persons can be divided into three equal groups is **280**.
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