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How many numbers lying between 999 and 1...

How many numbers lying between `999` and `10000` can be formed with the help of the digit `0,2,3,6,7,8` when the digits are not to be repeated

A

100

B

200

C

300

D

400

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AI Generated Solution

The correct Answer is:
To solve the problem of how many numbers can be formed between 999 and 10,000 using the digits 0, 2, 3, 6, 7, and 8 without repetition, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Range**: - We need to form 4-digit numbers that lie between 999 and 10,000. Therefore, all the numbers we form will be 4-digit numbers. 2. **Determine the First Digit**: - The first digit of a 4-digit number cannot be 0 (as it would not be a 4-digit number). - The possible digits for the first position are 2, 3, 6, 7, and 8. This gives us **5 options** for the first digit. 3. **Determine the Second Digit**: - After choosing the first digit, we can use 0 for the second digit. However, we cannot repeat the digit used in the first position. - Since we have already used one digit, we have **5 remaining digits** (including 0) to choose from for the second digit. 4. **Determine the Third Digit**: - For the third digit, we cannot use the digits already chosen for the first and second positions. - This leaves us with **4 remaining digits** to choose from for the third digit. 5. **Determine the Fourth Digit**: - For the fourth digit, we again cannot use the digits already chosen for the first, second, and third positions. - This leaves us with **3 remaining digits** to choose from for the fourth digit. 6. **Calculate the Total Combinations**: - The total number of combinations can be calculated by multiplying the number of choices for each digit: \[ \text{Total Combinations} = (\text{Choices for 1st digit}) \times (\text{Choices for 2nd digit}) \times (\text{Choices for 3rd digit}) \times (\text{Choices for 4th digit}) \] \[ = 5 \times 5 \times 4 \times 3 \] \[ = 300 \] ### Final Answer: Thus, the total number of 4-digit numbers that can be formed between 999 and 10,000 using the digits 0, 2, 3, 6, 7, and 8 without repetition is **300**. ---
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