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If 0ltthetaltpi, then the minimum value ...

If `0ltthetaltpi`, then the minimum value of `sin^(5)theta+"cosec"^(5)theta,` is

A

0

B

1

C

2

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the minimum value of \( \sin^5 \theta + \csc^5 \theta \) for \( 0 < \theta < \pi \), we can use the Arithmetic Mean-Geometric Mean (AM-GM) inequality. ### Step-by-Step Solution: 1. **Identify the terms**: We have two terms, \( \sin^5 \theta \) and \( \csc^5 \theta \). 2. **Apply the AM-GM Inequality**: According to the AM-GM inequality, for any non-negative real numbers \( a \) and \( b \): \[ \frac{a + b}{2} \geq \sqrt{ab} \] Here, let \( a = \sin^5 \theta \) and \( b = \csc^5 \theta \). 3. **Set up the inequality**: \[ \frac{\sin^5 \theta + \csc^5 \theta}{2} \geq \sqrt{\sin^5 \theta \cdot \csc^5 \theta} \] 4. **Simplify the right-hand side**: We know that \( \csc \theta = \frac{1}{\sin \theta} \), so: \[ \csc^5 \theta = \left(\frac{1}{\sin \theta}\right)^5 = \frac{1}{\sin^5 \theta} \] Therefore: \[ \sin^5 \theta \cdot \csc^5 \theta = \sin^5 \theta \cdot \frac{1}{\sin^5 \theta} = 1 \] 5. **Substitute back into the inequality**: \[ \frac{\sin^5 \theta + \csc^5 \theta}{2} \geq \sqrt{1} = 1 \] 6. **Multiply both sides by 2**: \[ \sin^5 \theta + \csc^5 \theta \geq 2 \] 7. **Conclusion**: The minimum value of \( \sin^5 \theta + \csc^5 \theta \) is \( 2 \). ### Final Answer: The minimum value of \( \sin^5 \theta + \csc^5 \theta \) is \( 2 \).
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