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If a(1),a(2),a(3) be any positive real n...

If `a_(1),a_(2),a_(3)` be any positive real numbers, then which of the following statement is not true.

A

`3a_(1),a_(2),a_(3)lea_(1)^(3)+a_(2)^(3)+a_(3)^(3)`

B

`(a_(1))/(a_(2))+(a_(2))/(a_(3))+(a_(3))/(a_(1))ge3`

C

`(a_(1)+a_(2)+a_(3))((1)/(a_(1))+(1)/(a_(2))+(1)/(a_(3)))ge9`

D

`(a_(1)+a_(2)+a_(3))((1)/(a_(1))+(1)/(a_(2))+(1)/(a_(3)))^(3)le27`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statement is not true among the given options regarding the positive real numbers \( a_1, a_2, a_3 \), we can utilize the properties of inequalities, specifically the Arithmetic Mean-Geometric Mean (AM-GM) inequality. Here’s a step-by-step solution: ### Step 1: Understand the AM-GM Inequality The AM-GM inequality states that for any non-negative real numbers \( x_1, x_2, \ldots, x_n \): \[ \frac{x_1 + x_2 + \ldots + x_n}{n} \geq \sqrt[n]{x_1 x_2 \ldots x_n} \] with equality if and only if all \( x_i \) are equal. ### Step 2: Apply AM-GM to \( a_1, a_2, a_3 \) For the positive real numbers \( a_1, a_2, a_3 \): \[ \frac{a_1 + a_2 + a_3}{3} \geq \sqrt[3]{a_1 a_2 a_3} \] This implies: \[ a_1 + a_2 + a_3 \geq 3\sqrt[3]{a_1 a_2 a_3} \] ### Step 3: Apply AM-GM to the Reciprocals Now, consider the reciprocals \( \frac{1}{a_1}, \frac{1}{a_2}, \frac{1}{a_3} \): \[ \frac{\frac{1}{a_1} + \frac{1}{a_2} + \frac{1}{a_3}}{3} \geq \sqrt[3]{\frac{1}{a_1 a_2 a_3}} \] This simplifies to: \[ \frac{1}{a_1} + \frac{1}{a_2} + \frac{1}{a_3} \geq \frac{3}{\sqrt[3]{a_1 a_2 a_3}} \] ### Step 4: Multiply the Two Inequalities Now, we multiply the two inequalities obtained: \[ (a_1 + a_2 + a_3) \left(\frac{1}{a_1} + \frac{1}{a_2} + \frac{1}{a_3}\right) \geq 9 \] This is derived from: \[ \left(3\sqrt[3]{a_1 a_2 a_3}\right) \left(\frac{3}{\sqrt[3]{a_1 a_2 a_3}}\right) = 9 \] ### Step 5: Identify the Incorrect Statement From the above derivation, we conclude that: \[ (a_1 + a_2 + a_3) \left(\frac{1}{a_1} + \frac{1}{a_2} + \frac{1}{a_3}\right) \geq 9 \] Thus, any statement contradicting this conclusion is not true. ### Conclusion We can analyze the given options to find which one does not hold true based on our derived inequality.
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