The value of C(0)+3C(1)+5C(2)+7C(3)+….+(...

The value of `C_(0)+3C_(1)+5C_(2)+7C_(3)+….+(2n+1)C_(n)` is equal to :

A

`""^(2n -1)C_(n-1)`

B

`(2n +1)""^(2n-1)C_(n)`

C

`2(n+1)*""^(2n-1)C_(n-1)`

D

`""^(2n-1)C_(n)+(2n+1)""^(2n-1)C_(n-1)`

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The correct Answer is:

C

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