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The vertex of a parabola is the point (a...

The vertex of a parabola is the point (a,b) and latusrectum is of length `l`. If the axis of the parabola is along the positive direction of y-axis, then its equation is :

A

`(x+a)^(2)=l/2(2 y-2b)`

B

`(x-a)^(2)=l/2(2 y-2b)`

C

`(x+a)^(2)=l/4(2 y-2b)`

D

`(x-a)^(2)=l/8(2 y-2b)`

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To find the equation of the parabola given the vertex (a, b) and the length of the latus rectum (l), we follow these steps: ### Step 1: Understand the standard form of the parabola Since the axis of the parabola is along the positive direction of the y-axis, the standard form of the equation of the parabola can be expressed as: \[ x^2 = 4Ay \] Here, \(A\) is a constant that determines the distance from the vertex to the focus. ### Step 2: Shift the parabola to the vertex (a, b) To shift the vertex from the origin (0, 0) to the point (a, b), we replace \(x\) with \(x - a\) and \(y\) with \(y - b\). Thus, the equation becomes: \[ (x - a)^2 = 4A(y - b) \] ### Step 3: Relate the latus rectum to the constant A The length of the latus rectum \(L\) of a parabola is given by the formula: \[ L = 4A \] From this, we can express \(A\) in terms of \(L\): \[ A = \frac{L}{4} \] ### Step 4: Substitute A into the equation Now, substituting \(A = \frac{L}{4}\) into the equation we derived in Step 2: \[ (x - a)^2 = 4\left(\frac{L}{4}\right)(y - b) \] This simplifies to: \[ (x - a)^2 = L(y - b) \] ### Final Equation Thus, the final equation of the parabola with vertex (a, b) and latus rectum of length \(L\) is: \[ (x - a)^2 = L(y - b) \]

To find the equation of the parabola given the vertex (a, b) and the length of the latus rectum (l), we follow these steps: ### Step 1: Understand the standard form of the parabola Since the axis of the parabola is along the positive direction of the y-axis, the standard form of the equation of the parabola can be expressed as: \[ x^2 = 4Ay \] Here, \(A\) is a constant that determines the distance from the vertex to the focus. ...
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The vertex of a parabola is the point (a , b) and the latus rectum is of length l . If the axis of the parabola is parallel to the y-axis and the parabola is concave upward, then its equation is a. (x+a)^2=1/2(2y-2b) b. (x-a)^2=1/2(2y-2b) c. (x+a)^2=1/4(2y-2b) d. (x-a)^2=1/8(2y-2b)

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OBJECTIVE RD SHARMA ENGLISH-PARABOLA-Chapter Test
  1. The vertex of a parabola is the point (a,b) and latusrectum is of leng...

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  2. If y=2x+k is a tangent to the curve x^(2)=4y, then k is equal to

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  3. The normal drawn at a point (a t1 2,-2a t1) of the parabola y^2=4a x m...

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  4. The mid-point of the chord 2x+y-4=0 of the parabola y^(2)=4x is

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  5. The two ends of latusrectum of a parabola are the points (3, 6) and (-...

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  6. Prove that the locus of the middle points of all chords of the parabol...

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  7. The focus of the parabola x^2-8x+2y+7=0 is

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  8. The point of contact of the line x-2y-1=0 with the parabola y^(2)=2(x-...

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  9. Find the number of distinct normals that can be drawn from (-2,1) to t...

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  10. At what point on the parabola y^2=4x the normal makes equal angle with...

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  11. Three normals to the parabola y^2= x are drawn through a point (C, O) ...

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  12. The normal chord of a parabola y^2= 4ax at the point P(x1, x1) subten...

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  13. AB, AC are tangents to a parabola y^2=4ax; p1, p2, p3 are the lengths...

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  14. The circles on the focal radii of a parabola as diameter touch: A) th...

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  15. If the normals from any point to the parabola y^2=4x cut the line x=2 ...

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  16. about to only mathematics

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  17. The equation of the tangent to the parabola y^(2)=8x which is perpendi...

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  18. the tangent drawn at any point P to the parabola y^2= 4ax meets the di...

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  19. about to only mathematics

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  20. The parabola y^(2)=4ax passes through the point (2,-6). Find the lengt...

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  21. A variable circle passes through the fixed point (2, 0) and touches y-...

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