Home
Class 11
MATHS
If m be the slope of common tangent of y...

If `m` be the slope of common tangent of `y = x^2 - x + 1` and `y = x^2 – 3x + 1`. Then `m` is equal to

A

16

B

7

C

9

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the slope \( m \) of the common tangent of the parabolas given by the equations \( y = x^2 - x + 1 \) and \( y = x^2 - 3x + 1 \), we can follow these steps: ### Step 1: Rewrite the equations in standard form The first parabola is: \[ y = x^2 - x + 1 \] We can complete the square: \[ y = \left(x - \frac{1}{2}\right)^2 + \frac{3}{4} \] This shows that the vertex is at \( \left(\frac{1}{2}, \frac{3}{4}\right) \). The second parabola is: \[ y = x^2 - 3x + 1 \] Completing the square gives: \[ y = \left(x - \frac{3}{2}\right)^2 - \frac{5}{4} \] This shows that the vertex is at \( \left(\frac{3}{2}, -\frac{5}{4}\right) \). ### Step 2: Write the equations of the tangents The general equation of the tangent to a parabola \( y = ax^2 + bx + c \) at a point \( (x_0, y_0) \) is given by: \[ y - y_0 = m(x - x_0) \] For the first parabola, the equation of the tangent can be expressed as: \[ y - \frac{3}{4} = m\left(x - \frac{1}{2}\right) - \frac{m^2}{4} \] Rearranging gives: \[ y = mx - \frac{m}{2} + \frac{3}{4} - \frac{m^2}{4} \] For the second parabola, the equation of the tangent is: \[ y + \frac{5}{4} = m\left(x - \frac{3}{2}\right) - \frac{m^2}{4} \] Rearranging gives: \[ y = mx - \frac{3m}{2} - \frac{5}{4} - \frac{m^2}{4} \] ### Step 3: Set the equations equal to find the slope Since both tangents are common, we set the right-hand sides of both equations equal: \[ mx - \frac{m}{2} + \frac{3}{4} - \frac{m^2}{4} = mx - \frac{3m}{2} - \frac{5}{4} - \frac{m^2}{4} \] This simplifies to: \[ -\frac{m}{2} + \frac{3}{4} = -\frac{3m}{2} - \frac{5}{4} \] Now, simplify and solve for \( m \): \[ -\frac{m}{2} + \frac{3}{4} + \frac{3m}{2} + \frac{5}{4} = 0 \] Combining like terms: \[ \frac{2m}{2} + \frac{8}{4} = 0 \] This simplifies to: \[ m + 2 = 0 \quad \Rightarrow \quad m = -2 \] ### Final Answer Thus, the slope \( m \) of the common tangent is: \[ \boxed{-2} \]

To find the slope \( m \) of the common tangent of the parabolas given by the equations \( y = x^2 - x + 1 \) and \( y = x^2 - 3x + 1 \), we can follow these steps: ### Step 1: Rewrite the equations in standard form The first parabola is: \[ y = x^2 - x + 1 \] We can complete the square: ...
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section I - Solved Mcqs|66 Videos
  • PARABOLA

    OBJECTIVE RD SHARMA ENGLISH|Exercise SECTION-I (SOLVED MCQs EXAMPLE)|1 Videos
  • PAIR OF STRAIGHT LINES

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|18 Videos
  • PERMUTATIONS AND COMBINATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|60 Videos

Similar Questions

Explore conceptually related problems

Find the slope of the tangent to the curve y = x^3- x at x = 2 .

If m be the slope of common tangent to the circle x^2 + y^2 = 16 and ellipse x^2/25+y^2/4=1 in the first quadrant, then 81m^8 =

If m be the slope of the tangent to the curve e^(2y) = 1+4x^(2) , then

Sum of slopes of common tangent to y = (x^(2))/(4) - 3x +10 and y = 2 - (x^(2))/(4) is (a) -6 (b) -3 (c) 1/2 (d) none of these

Slope of tangent to x^(2)=4y from (-1, -1) can be

The common tangent of the curves y=x^(2) +(1)/(x) " and " y^(2) =4 x is

If m is the slope of common tangent lo circle x^(2)+y^(2 )= c^(2) and the parabola y^(2 )= 4ax then find the value of m^(2)

The slope of the curve y = x^(3) - 2x+1 at point x = 1 is equal to :

The equation of common tangent to the parabola y^2 =8x and hyperbola 3x^2 -y^2=3 is

The slope of the tangent at the point of inflection of y = x ^(3) -3x ^(2)+ 6x +2009 is equal to :

OBJECTIVE RD SHARMA ENGLISH-PARABOLA-Chapter Test
  1. If m be the slope of common tangent of y = x^2 - x + 1 and y = x^2 – 3...

    Text Solution

    |

  2. If y=2x+k is a tangent to the curve x^(2)=4y, then k is equal to

    Text Solution

    |

  3. The normal drawn at a point (a t1 2,-2a t1) of the parabola y^2=4a x m...

    Text Solution

    |

  4. The mid-point of the chord 2x+y-4=0 of the parabola y^(2)=4x is

    Text Solution

    |

  5. The two ends of latusrectum of a parabola are the points (3, 6) and (-...

    Text Solution

    |

  6. Prove that the locus of the middle points of all chords of the parabol...

    Text Solution

    |

  7. The focus of the parabola x^2-8x+2y+7=0 is

    Text Solution

    |

  8. The point of contact of the line x-2y-1=0 with the parabola y^(2)=2(x-...

    Text Solution

    |

  9. Find the number of distinct normals that can be drawn from (-2,1) to t...

    Text Solution

    |

  10. At what point on the parabola y^2=4x the normal makes equal angle with...

    Text Solution

    |

  11. Three normals to the parabola y^2= x are drawn through a point (C, O) ...

    Text Solution

    |

  12. The normal chord of a parabola y^2= 4ax at the point P(x1, x1) subten...

    Text Solution

    |

  13. AB, AC are tangents to a parabola y^2=4ax; p1, p2, p3 are the lengths...

    Text Solution

    |

  14. The circles on the focal radii of a parabola as diameter touch: A) th...

    Text Solution

    |

  15. If the normals from any point to the parabola y^2=4x cut the line x=2 ...

    Text Solution

    |

  16. about to only mathematics

    Text Solution

    |

  17. The equation of the tangent to the parabola y^(2)=8x which is perpendi...

    Text Solution

    |

  18. the tangent drawn at any point P to the parabola y^2= 4ax meets the di...

    Text Solution

    |

  19. about to only mathematics

    Text Solution

    |

  20. The parabola y^(2)=4ax passes through the point (2,-6). Find the lengt...

    Text Solution

    |

  21. A variable circle passes through the fixed point (2, 0) and touches y-...

    Text Solution

    |