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The equation of the parabola, whose vert...

The equation of the parabola, whose vertex and focus are on the x-axis at distances a and b from the origin respectively, is :

A

`y^(2)=4(b-a)(x-a)`

B

`y^(2)=4(b-b)(x-b)`

C

`y^(2)=4(b-a)(x-a)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A

We have,
AS=Distance between the vertex and focus =b-a

`:." "L.R.=4(b-a)`
So, the equation of the parabola having vertex at the origin and
`L.R.=4(b-a)is`
`y^(2)=4(b-a)x" ...(i)"`
Clearly, required parabola is obtained by translating (i) through distance 'a' along positive direction of x-axis. So, its equation is
`y^(2)=4(b-a)(x-a).`
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