Home
Class 11
MATHS
the shortest distance between the lin...

the shortest distance between the line `y-x=1` and the curve `x=y^(2)` is

A

`sqrt3/4`

B

`(3sqrt2)/8`

C

`8/(3sqrt2)`

D

`4/sqrt3`

Text Solution

Verified by Experts

The correct Answer is:
B

Let `P(t^(2), t)` be point on the curve `x-=y^(2)` and S be the distance between P and the line `y-x-1=0`. Then, `S=|(t-t^(2)-1)/(sqrt(1+1))|=(t^(2)-t+1)/(sqrt2)=1/sqrt2{(t-1/2)^(2)+(sqrt3/2)^(2)}`
Clearly, S is minimum when`t=1/2`
For this value of t, we get
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    OBJECTIVE RD SHARMA ENGLISH|Exercise SECTION-I (SOLVED MCQs EXAMPLE)|1 Videos
  • PARABOLA

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section II - Assertion Reason Type|7 Videos
  • PARABOLA

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|30 Videos
  • PAIR OF STRAIGHT LINES

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|18 Videos
  • PERMUTATIONS AND COMBINATIONS

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|60 Videos

Similar Questions

Explore conceptually related problems

The shortest distance between the line x=y and the curve y^(2)=x-2 is

Find the shortest distance between the line x - y +1 = 0 and the curve y^2 = x.

The shortest distance between line y-x=1 and curve x=y^2 is (a) (3sqrt2)/8 (b) 8/(3sqrt2) (c) 4/sqrt3 (d) sqrt3/4

The shortest distance between line y"-"x""=""1 and curve x""=""y^2 is : (1) (sqrt(3))/4 (2) (3sqrt(2))/8 (3) 8/(3sqrt(2)) (4) 4/(sqrt(3))

The shortest distance between the point (0, 1/2) and the curve x = sqrt(y) , (y gt 0 ) , is:

Find the shortest distance between the line y=x-2 and the parabola y=x^2+3x+2.

Find the shortest distance between the line y=x-2 and the parabola y=x^2+3x+2.

Find the shortest distance between the line y=x-2 and the parabola y=x^2+3x+2.

If each a_i > 0 , then the shortest distance between the points (0,-3) and the curve y=1+a_1x^2+a_2 x^4+.......+a_n x^(2n) is

Find the shortest distance between the line y=x-2 and the parabola y=x^2+3x+2

OBJECTIVE RD SHARMA ENGLISH-PARABOLA-Section I - Solved Mcqs
  1. The locus of the midpoint of the segment joining the focus to a moving...

    Text Solution

    |

  2. The radical centre of the circles drawn on the focal chords of y^(2)=4...

    Text Solution

    |

  3. For each parabola y=x^(2)+px+q, meeting coordinate axes at 3-distinct ...

    Text Solution

    |

  4. Let A(x(1),y(1)) and B(x(2),y(2)) be two points on the parabola y^(2) ...

    Text Solution

    |

  5. Let A and B be two distinct points on the parabola y^2=4x. If the ax...

    Text Solution

    |

  6. the shortest distance between the line y-x=1 and the curve x=y^(2) ...

    Text Solution

    |

  7. about to only mathematics

    Text Solution

    |

  8. Let PQ be a focal chord of the parabola y^(2)=4ax. The tangents to the...

    Text Solution

    |

  9. Let a, r, s, t be non-zero real numbers. Let P(at^(2),2at),Q(ar^(2),2a...

    Text Solution

    |

  10. Let a, r, s, t be non-zero real numbers. Let P(at^(2),2at),Q(ar^(2),2a...

    Text Solution

    |

  11. Let P and Q be distinct points on the parabola y^2 = 2x such that a c...

    Text Solution

    |

  12. about to only mathematics

    Text Solution

    |

  13. PSQ is a focal chord of a parabola whose focus is S and vertex is A. P...

    Text Solution

    |

  14. Let P be the point on the parabola y^(2)4x which is at the shortest di...

    Text Solution

    |

  15. Let P be the point on the parabola, y^(2)=8x which is at a minimum dis...

    Text Solution

    |

  16. P and Q are two distinct points on the parabola, y^2 = 4x with paramet...

    Text Solution

    |

  17. Let PQ be a focal chord of the parabola y^(2)=4x. If the centre of a c...

    Text Solution

    |

  18. The centres of those circles which touch the circle, x^(2)+y^(2)-8x-8y...

    Text Solution

    |

  19. The radius of a circle, having minimum area, which touches the curve...

    Text Solution

    |

  20. If a chord , which is not a tangent of the parabola y^2=16x has the eq...

    Text Solution

    |