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The two parabolas y^(2)=4x" and "x^(2)=4...

The two parabolas `y^(2)=4x" and "x^(2)=4y` intersect at a point P, whose abscissas is not zero, such that

A

they both touch each other at P

B

they cut at right angles at P

C

the tangents to each curvs at P make complementary angles with the x-axis

D

none of these

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The correct Answer is:
To solve the problem of finding the intersection points of the parabolas \( y^2 = 4x \) and \( x^2 = 4y \), we will follow these steps: ### Step 1: Set the equations equal to each other We have two equations: 1. \( y^2 = 4x \) 2. \( x^2 = 4y \) To find the points of intersection, we can express \( y \) in terms of \( x \) from the first equation and substitute it into the second equation. ### Step 2: Substitute \( y \) from the first equation into the second From \( y^2 = 4x \), we can express \( y \) as: \[ y = \sqrt{4x} = 2\sqrt{x} \] Now, substitute \( y \) into the second equation \( x^2 = 4y \): \[ x^2 = 4(2\sqrt{x}) \implies x^2 = 8\sqrt{x} \] ### Step 3: Rearrange the equation Rearranging gives: \[ x^2 - 8\sqrt{x} = 0 \] Let \( \sqrt{x} = t \), then \( x = t^2 \). Substituting \( t \) into the equation gives: \[ (t^2)^2 - 8t = 0 \implies t^4 - 8t = 0 \] Factoring out \( t \): \[ t(t^3 - 8) = 0 \] ### Step 4: Solve for \( t \) Setting each factor to zero gives: 1. \( t = 0 \) (which corresponds to \( x = 0 \)) 2. \( t^3 - 8 = 0 \implies t^3 = 8 \implies t = 2 \) (which corresponds to \( x = 4 \)) ### Step 5: Find the corresponding \( y \) values For \( t = 2 \): \[ \sqrt{x} = 2 \implies x = 4 \] Now substitute \( x = 4 \) back into the first equation to find \( y \): \[ y^2 = 4(4) = 16 \implies y = 4 \text{ or } y = -4 \] Thus, the points of intersection are: 1. \( (0, 0) \) (which we discard since the abscissa is zero) 2. \( (4, 4) \) 3. \( (4, -4) \) ### Step 6: Verify the conditions The problem states that we need to find the point \( P \) whose abscissa is not zero. Therefore, the valid points are \( (4, 4) \) and \( (4, -4) \). ### Conclusion The two parabolas intersect at the points \( (4, 4) \) and \( (4, -4) \), where the abscissa is not zero. ---
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OBJECTIVE RD SHARMA ENGLISH-PARABOLA-Exercise
  1. Normal at the point P(a p^2,2a p) meets the parabola y^2=4a x again at...

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  2. The length of the subnormal to the parabola y^(2)=4ax at any point is ...

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  3. The two parabolas y^(2)=4x" and "x^(2)=4y intersect at a point P, whos...

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  4. A set of parallel chords of the parabola y^2=4a x have their midpoint ...

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  5. Find the point on the curve y^(2)=ax the tangent at which makes an ang...

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  6. If 2x+y+lamda=0 is a normal to the parabola y^(2)=-8x, then lamda is

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  7. Find the angle at which the parabolas y^2=4x and x^2=32 y intersect.

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  8. The normal at (a,2a) on y^2 = 4ax meets the curve again at (at^2, 2at)...

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  9. If a chord which is normal to the parabola at one end subtend a right ...

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  10. Find the equations of the normals at the ends of the latus- rectum of ...

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  11. Normal at the point P(a p^2,2a p) meets the parabola y^2=4a x again at...

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  12. If the normals at points t1 and t2 meet on the parabola, then (a) t1...

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  13. If the normals at two points P and Q of a parabola y^2 = 4ax intersect...

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  14. Find the angle between the tangents drawn from the origin to the pa...

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  15. The angle between the tangents drawn from the point (-a, 2a) to y^2=4a...

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  16. The angle between the tangents to the parabola y^2=4a x at the points ...

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  17. P(-3, 2) is one end of focal chord PQ of the parabola y^2+4x+4y=0. The...

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  18. If x=my+c is a normal to the parabola x^(2)=4ay, then the value of c, ...

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  19. Find the equations of the tangent to the given curve at the indicated...

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  20. The tangents at the points (at(1)^(2), 2at(1)), (at(2)^(2), 2at(2)) on...

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